Check whether a number is present in an array - simple java coding

/*check an number present in an array or not*/

import java.io.*;

class check

{

public static void main (String args[]) throws IOException

{

DataInputStream s = new DataInputStream(System.in);

int n,i,x,flag;

flag=0;

int a[] = new int [100];

System.out.println("Enter the number of elements");

n= Integer.parseInt(s.readLine());

  System.out.println("Enter the "+n+"numbers");

  for(i=0;i<n;i++)

  {

    a[i]=Integer.parseInt(s.readLine());

  }

  System.out.println("Enter the number you want to search");

  x=Integer.parseInt(s.readLine());

  for(i=0;i<n;i++)

  {

    if(a[i]==x)

    {

     flag++;

    }

  }

  if(flag==0)

  {

    System.out.println(x+" IS NOT PRESENT");

  }

  else

  {

    System.out.println(x+ " IS PRESENT FOR " +flag+ " TIMES");

  }

}

}

Save the file with the extension . java and open the command prompt.

C:\Documents and Settings\dcom358>H:

H:\>cd java

H:\Java>path=C:\jdk1.3\bin;

H:\Java>javac check.java

Note: check.java uses or overrides a deprecated API.

Note: Recompile with -deprecation for details.

H:\Java>java check

Enter the number of elements

5

Enter the 5numbers

100

200

100

300

400

Enter the number you want to search

100

100 IS PRESENT FOR 2 TIMES

H:\Java>java check

Enter the number of elements

5

Enter the 5numbers

2650

2354

5286

2547

26478

Enter the number you want to search

2355

2355 IS NOT PRESENT